Question

Hitunglah koefisien c dan d dari
7x-12 / (x-4)(x+3) = C / X-4 + D / X+3 ADALAH

Answer 1

(7x -12)/(x-4)(x +3) = c/(x-4) + D(x+3) 
(7x -12) / (x-4)(x-3) = {c(x+3) + d(x-4) }/(x-4)(x+3)
(7x-12)/(x-4)(x-3) = (Cx + 3C + Dx - 4D)/(x-4)(x+3)
(7x-12)/(x-4)(x+3) = (C+D) x + (3C-4D) / (x-4)(x-3)
7x -12 = (C+D)x + (3C-4D)

C+D = 7
3C-4D = -12
eliminasikan
3C + 3D= 21
3C-4D = -12
...
7D = 33 -> D = 33/7
C = 7 - D = 16/7