Question

X^3-7x+6=(x+3)(x-2)(x-t)
tentukan nilai t

Answer 1

X^3-7x+6=(x+3)(x-2)(x-t)
X^3-7x+6= (x^2 + x -6) (x-t)
X^3-7x+6= x^3 - tx^2 +x^2-tx-6x +6t
X^3-7x+6= x^3 -(t-1)x^2 - (t+6)x +6t

6t =6
t=1

Answer 2

X³-7x+6 = (x+3)(x-2)(x-t)
x³-7x+6 = (x²+x-6)(x-t)
x³-7x+6 = x³-tx²+x²-xt-6x+6t
x³-7x+6 = x³+(1-t)x²-(6+t)x+6t

*6t = 6
   t = 6/6
     = 1
*(6+t)x = 7x
     6+t  = 7
          t = 7-6
            = 1