Wyznacz dziedzinę funkcji:
f(x) = 1/x^2+6x-7
x^2+6x-7≠0 a=1 b=6 c=-7
delta=36+28=64
√delta=8
x1=-7
x2=1
D=R-{-7, 1}
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x^2+6x-7≠0 a=1 b=6 c=-7
delta=36+28=64
√delta=8
x1=-7
x2=1
D=R-{-7, 1}