(x+2)(3-x)≥x
3x-x²+6-2x-x≥0
-x²+6≥0
x²-6≤0
x∈<-√6; √6>
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
(x+2)(3-x)≥x
3x-x²+6-2x-x≥0
-x²+6≥0
x²-6≤0
x∈<-√6; √6>