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-2 < -x²+2x-2 < 2
Masalah 1:
-x²+2x-2 ≥ 0
x²-2x+2 < 0
Tidak ada solusi mengingat Diskriminannya dibawah 0 (Definit positif)
Masalah 2:
-x²+2x-2 < 0
x²-2x+2 > 0 (Seluruh bilangan real)
Maka,
Asumsi mutlak negatif:
-(-x²+2x-2) < 2
x²-2x+2 < 2
x²-2x < 0
x(x-2) < 0
Didapat solusi
0 < x < 2