Rozwiaz nierownosc x-4/x+2 < 4 daje naj !
x-4 / x+2 <4
D=R\{-2}
-x²-6x-8<0
Δ=36-32=4
√Δ=2
x₁=6-2 /-2=4/-2=-2
x₂=6+2 /-2=8/-2=-4
załącznik
x∈(-∞;-4)u(-2;+∞)
(x-4)/(x+2) < 4 ------------------- D = R / {-2)
[(x - 4) - 4(x + 2) ] / (x + 2) < 0
[ x - 4 - 4x - 8 ] / (x + 2) < 0
( -3x - 12) / (x +2) < 0
-3(x + 4)(x + 2) < 0------ / : (-3)
(x + 4)(x + 2) > 0
x nalezy (-oo, -4) u ( -2, +oo)
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x-4 / x+2 <4
D=R\{-2}
-x²-6x-8<0
Δ=36-32=4
√Δ=2
x₁=6-2 /-2=4/-2=-2
x₂=6+2 /-2=8/-2=-4
załącznik
x∈(-∞;-4)u(-2;+∞)
(x-4)/(x+2) < 4 ------------------- D = R / {-2)
[(x - 4) - 4(x + 2) ] / (x + 2) < 0
[ x - 4 - 4x - 8 ] / (x + 2) < 0
( -3x - 12) / (x +2) < 0
-3(x + 4)(x + 2) < 0------ / : (-3)
(x + 4)(x + 2) > 0
x nalezy (-oo, -4) u ( -2, +oo)