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√Δ=b²-4ac=49-4*3*4=49-48=√1=1
x1=-b-√Δ\2a=-7-1\6=-8\6=-4\3
x2=-7+1\6=-6\6=-1
(3x+4)(x+1) \(x+1) =5 (skracamy (x+1)
3x+4=5
3x=1 /÷3
x=1\3
b)
x²-4x+4=0 √Δ=b²-4ac=16-4*1*4=16-16=0 x0=-b\2a=4\2=2
2x-3\x²-4x+4= -1
2x-3\x-2=-1
2x-3=x-2
2x-x=-2+3
x=1