Question

x²+12x-13=0 (tentukan akar persamaan kuadrat berikut dengan rumus abc!)​

Answer 1

Jawaban:

x²+12x-13=0

-12±√12²-4.1.-13/2.1

-12±√144-(-52)/2

-12±√196/2

-12±14/2

x1 = -12-14/2 = -26/2 = -13

x2 = -12+14/2 = 2/2 = 1

hp{-13,1}