Potrzebne na już! Znajdź X : 3/x^2-1 + x/x-1 = 11-x/x+1
zał. (x-1)(x+1)≠0
x∈R\{-1 , 1}
3 x 11-x
------- + ------- = --------- /*(x-1)(x+1)
x²-1 x-1 x+1
3 + x(x+1) = (11-x)(x-1)
3 + x² + x = 11x - 11-x² + x
x² + x² + x -11x-x+3+11 = 0
2x²-11x + 14 = 0
Δ=b²-4ac = 121 -112 = 9 √Δ =3
x1=(-b-√Δ)/2a = (11-3)/4 = 8/2=2
x2 = (-b+√Δ)/2a = (11+3)/4 = 3 1/2
odp:
x= 2 U x = 3 1/2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
zał. (x-1)(x+1)≠0
x∈R\{-1 , 1}
3 x 11-x
------- + ------- = --------- /*(x-1)(x+1)
x²-1 x-1 x+1
3 + x(x+1) = (11-x)(x-1)
3 + x² + x = 11x - 11-x² + x
x² + x² + x -11x-x+3+11 = 0
2x²-11x + 14 = 0
Δ=b²-4ac = 121 -112 = 9 √Δ =3
x1=(-b-√Δ)/2a = (11-3)/4 = 8/2=2
x2 = (-b+√Δ)/2a = (11+3)/4 = 3 1/2
odp:
x= 2 U x = 3 1/2