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(3x+10)(x-2)
3x+10=0. atau. x-2=0
3x= -10. x=2
x= -10/3.
jadi x1= -10/3. dan x2=2
a.x1+x2= -10/3+2 =-10/3+6/3= -4/3
b.x1 .x2 =-10/3 x2 =- 20/3 = -6 2/3
c.1/x1+ 1/x2 = 1/-10/3+1/2= -3/10+1/2 =-3/10+5/10=2/10 =1/5
d x1/x2 +x2/x1 = (-10/3: 2)+(2:-10/3)=-20/3+(-6/10)
=20/3-6/10=200/30-18/30=182/30=91/15 = 6 1/15