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w(x)=(x-1)³
x-1=0
x=1
2.W(x)=x³-3x²-2x+6
w(x)=x²(x-3)+2(x-3)
w(x)=(x²+2)(x-3)
x²+2=0 ∧ x-3=0
x²=-2 /√ ∧ x=3
x∈Ф ∧ x=3
3.-6x²+5x-1>0
Δ=5²- 4(-6)(-1)=25-24=1
√Δ=1
x₁=-5-1/2*-6= -6/-36=1/6 x₂=-5+1/2*-6=-4/-36=1/9
odp: x∈(1/6;1/9)
4.16x²-8x+1>0
Δ=64 -64=0
x₁,₂=8/4*16=8/64=1/8
odp: x∈(1/8;⁺∞)
5.2x-3/x+1 -1=0 /*x+1
2x-3-1=0
2x=4 /:2
odp:x=2
6.W(x)=5x⁵+4x⁴+3x³+2x²+ax , o ktorym wiadomo ze W(1)=W(-1). Wykaz ze a =-8
5*1⁵+4*1⁴+3*1³+2*1²+a1=5*-1⁵+4*-1⁴+3*-1³+2*-1²+a-1
5+4+3+2+a=-5+4-3+2-a
14+a=-2-a
2a=-16 /:2
a=-8