Respuesta:
Explicación paso a paso:
[x] ={2x; si "x" es par} {x; si "x" es impar}
[3] como 3 es impar: [3] = 3
[5-3] = [2] como 2 es par: [2] = 4
[7] como 7 es impar: [7] = 7
La operación [[3]+7[5-3]]-[7] queda:
[3+7×4]-7
= [3+28]-7
= [31]-7
= 31-7 = 24
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