Question

Integral
1. ∫-1/y² dy - ∫ 1/x² dx =

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Answer 1

1. ∫-1/y² dy - ∫1/x²dx=
= -∫y⁻2 dy - ∫x⁻² dx
= - (1)(y⁻¹) - (-1)(x)⁻¹ + C
= -1/y + 1/x + C
= (y-x)/(xy) + C