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misal,
u = ln|1/x|
du = -(1/x) dx
dv = dx
v = x
uv - ∫v du = ln|1/x|.x - ∫x (-(1/x)) dx
= x.ln|1/x| - ∫-dx
= x.ln|1/x| + ∫dx
= x.ln|1/x| + x + C
= (ln|1/x| + 1)x + C