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x³-7x²-2x+14=0
x²(x-7)-2(x-7)=(x-7)(x²-2)=(x-7)(x-√2)(x+√2)=0
zatem
x=7 , x=-√2 i x=√2
Dziedzina : x∈R/{-√2,√2,7}
x³-7x²-2x+14≠0
x²(x-7)-2(x-7)≠0
(x²-2)(x-7)≠0
(x-√2)(x+√2)(x-7)≠0
x≠√2∧ x≠-√2 ∧x≠7
D=R\{-√2,√2,7}