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a=1
b=-5
c=6
Δ=b²-4ac=(-5)²-4*1*6=25-24=1
√Δ=√1=1
x₁=(-b+√Δ)/2a=(5+1)/2=6/2=3
x₂=(-b-√Δ)/2a=(5-1)/2=4/2=1
x²-5x+6=(x-3)(x-1)
Δ=b²-4ac
Δ=25-24=1
x₁=(-b-√Δ):2a
x₁=2
x₂=(-b+√Δ):2a
x₂=3
x²-5x+6=0
Δ=b²-4ac
Δ=25-24=1
x₁=(-b-√Δ):2a
x₁=2
x₂=(-b+√Δ):2a
x₂=3
proszeeeeeeee ;)