" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x² + 3x - 10 = 0
ax + bx + c = 0
ax + bx + c = (ax + p)(ax + q) = a.x² + a.q.x + a.p.x + p.q
a.c = p.q
p + q = b
1.-10 = 5.-2
5 + (-2) = 3
(1.x + 5)(1.x + (-2)) = 0
(x + 5)(x - 2) = 0
x + 5 = 0 atau x - 2 = 0
x = -5 atau x = 2
Cek :
ax² + aqx + apx + pq = 1.x² + 1.(-2x) + 1.(5x) + 5.-2 =
x² -2x + 5x - 10 = x² + 3x -10 = 0
Mungkin itu, maaf kalo salah
Jangan lupa, jadikan jawaban tercerdas,... Makasih :)