Podaj dziedzinę D funkcji określonej wzorem: y= 5/(x+1)
y= (- 3x)/((x-2)(x+5))
y= √(6x-8)
y=5/(x+1)
x+1≠0x≠-1Dy=R\{-1}y=(-3x)/((x-2)(x+5))(x-2)(x+5)≠0x²+5x-2x-10≠0x²+3x-10≠0Δ=9+40=49 √Δ=7x≠-5 v x≠2Dy=R\{-5,2}y=√(6x-8)6x-8≥06x≥8x≥1⅓Dy=<1⅓,+∞)
a)
x e R\{-5,2}
c)
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y=5/(x+1)
x+1≠0
x≠-1
Dy=R\{-1}
y=(-3x)/((x-2)(x+5))
(x-2)(x+5)≠0
x²+5x-2x-10≠0
x²+3x-10≠0
Δ=9+40=49 √Δ=7
x≠-5 v x≠2
Dy=R\{-5,2}
y=√(6x-8)
6x-8≥0
6x≥8
x≥1⅓
Dy=<1⅓,+∞)
a)
x e R\{-5,2}
c)