Question

X²-(2a+3)x+3a=0 mempunyai akar² berkebalikan,nilai a yg memenuhi adalah?

Answer 1

Verified answer

Jika akar berkebalikan , maka :
x1 = 1/x2.

x^2 - (2a + 3) + 3a = 0

a = 1 , b = - (2a + 3) dan c = 3a (a sbg variabel.)
Maka :
x1 . x2 = c/a
1/x2 . x2 = c/a
1 = c/a
3a/1 = 1
3a = 1
a = 1/3

Answer 2

Verified answer

Bab Persamaan Kuadrat
Matematika SMP Kelas VIII

x² - (2a + 3) x + 3a = 0
p = 1; q = -2a - 3; r = 3a

berkebalikan
r = p
3a = 1
a = 1/3