Penjelasan dengan langkah-langkah:
a. y = (x + 2)(3x - 1)
u(x) = x + 2
u'(x) = 1
v(x) = 3x - 1
v'(x) = 3
y' = u'(x) . v(x) + v'(x) . u(x)
y' = 1(3x - 1) + 3(x + 2)
y' = 3x - 1 + 3x + 6
y' = 6x + 5
b. (2x + 1)/(x + 2)
u(x) = 2x + 1
u'(x) = 2
v(x) = x + 2
v'(x) = 1
y' = u'(x) . v(x) - v'(x) . u(x)/v(x)²
y' = 2(x + 2) - 1(2x + 1)/(x + 2)²
y' = (2x + 4 - 2x - 1)/(x + 2)²
y' = 3/(x + 2)²
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Verified answer
Penjelasan dengan langkah-langkah:
a. y = (x + 2)(3x - 1)
u(x) = x + 2
u'(x) = 1
v(x) = 3x - 1
v'(x) = 3
y' = u'(x) . v(x) + v'(x) . u(x)
y' = 1(3x - 1) + 3(x + 2)
y' = 3x - 1 + 3x + 6
y' = 6x + 5
b. (2x + 1)/(x + 2)
u(x) = 2x + 1
u'(x) = 2
v(x) = x + 2
v'(x) = 1
y' = u'(x) . v(x) - v'(x) . u(x)/v(x)²
y' = 2(x + 2) - 1(2x + 1)/(x + 2)²
y' = (2x + 4 - 2x - 1)/(x + 2)²
y' = 3/(x + 2)²