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Cari titik potong sumbu x (y=0)y=2x²-20x+32/x²-16x+60
0=2x²-20x+32/x²-16x+60
2x²-20x+32 = 0
X²-10x+16=0
(x-8)(x-2)= 0
X= 8 atau x = 2
jadi titik potong sb x (8,0) dan (2,0)
Titik potong sumbu y (x= 0)
y=2x²-20x+32/x²-16x+60
y= 32/60 = 8/15
Jadi titik potong sb y (0,8/15)
Asimtot tegak( penyebut =0)
x²-16x+60=0
(x-10)(x-6)=0
x=10 dan x = 6
Asimtot datar ( x--> ~)
y=2x²-20x+32/x²-16x+60,
y = 2/1
Y= 2
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