Wyznacz zbiór wartości funkcji f(t)=2t²-t
jeżeli t∈<-1,1>
f(t) = 2t² - t t ∈ <-1, 1>
p = -b / 2a = 1 / 4
Δ = 1 - 4 * 2 * 0 = 1
q = - Δ / 4a = - 1/8
W = (p, q) = (1/4 ; - 1/8) ---- wierzchołek paraboli
f(-1) = 2 * (-1)² - (-1) = 2 * 1 + 1 = 2 + 1 = 3
f(1) = 2 * 1² - 1 = 2 * 1 - 1 = 2 - 1 = 1
odp. y ∈ < - 1/8, 3>
patrz zalacznik
f(t)=2t²-t=t(2t-1)
t1=0 t2=1/2
p=1/4
q=f(1/4)=1/8-1/4=-1/8
f∈<-1/8 , 3>
Pozdr
Hans
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f(t) = 2t² - t t ∈ <-1, 1>
p = -b / 2a = 1 / 4
Δ = 1 - 4 * 2 * 0 = 1
q = - Δ / 4a = - 1/8
W = (p, q) = (1/4 ; - 1/8) ---- wierzchołek paraboli
f(-1) = 2 * (-1)² - (-1) = 2 * 1 + 1 = 2 + 1 = 3
f(1) = 2 * 1² - 1 = 2 * 1 - 1 = 2 - 1 = 1
odp. y ∈ < - 1/8, 3>
patrz zalacznik
f(t)=2t²-t=t(2t-1)
t1=0 t2=1/2
p=1/4
q=f(1/4)=1/8-1/4=-1/8
f∈<-1/8 , 3>
Pozdr
Hans