Wyznacz zbiór elementow spelniajacych podane formy zdaniowe:
a) r(x):(3x+5)(2x-1)=0 v 4xkwadrat-1=0
b) s(x):9-4xkwadrat=0 v (3-2x)(x-5)=0
c) w(x): √x-1=0 ^ (x-1)(x+2)=0
d) v(x): 2- √x=0 ^ (2x-8)(x+1)=0
^=i
v=lub
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a)
r(x) : (3x +5)(2x -1) = 0 ∨ 4x² - 1 = 0
(3x + 5)(2x -1) = 0 ∨ (2x -1)(2x +1) = 0
3x = -5 ∨ 2x = 1 ∨ 2x =1 ∨ 2x = -1
x = -5/3 ∨ x = 1/2 ∨ x = 1/2 ∨ x = - 1/2
Odp. { -5/3; -1/2; 1/2 }
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b)
s(x) : 9 - 4x² = 0 ∨ (3 -2x)(x - 5) = 0
( 3 - 2x)(3 + 2x) = 0 ∨ (3 -2x)(x - 5) = 0
3 -2x = 0 ∨ 3 + 2x = 0 ∨ 3 -2x = 0 ∨ x - 5 = 0
2x = 3 ∨ 2x = -3 ∨ 2x = 3 ∨ x = 5
x = 3/2 ∨ x = -3/2 ∨ x = 3/2 ∨ x = 5
Odp. { -1,5 ; 1,5 ; 5 }
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c)
w(x) : √x - 1 = 0 ∧ (x -1)(x + 2) = 0
√x - 1 = 0 ∧ ( x -1 = 0 ∨ x + 2 = 0 )
√x = 1 ∧ ( x = 1 ∨ x = -2 )
( x = 1 ∧ x = 1 ) ∨ (x = 1 ∧ x = -2 )
x = 1
Odp. { 1 }
---------------------------
d)
v(x) : 2 - √x = 0 ∧ (2x - 8)(x + 1) = 0
2 - √x = 0 ∧ ( 2x - 8 = 0 ∨ x + 1 = 0 )
2 = √x ∧ (2x = 8 ∨ x = -1 )
( x = 4 ∧ x = 4 ) ∨ ( x = 4 ∧ x = -1 )
x = 4
Odp. { 4 }
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