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bx+ba=c
bx=c - ba /: b
x=c - a
b)(x-a)b=c+a
bx +ba = c+a
bx=c+a-ba /:b
x=c+a-a
x=c
bx+ab=c
bx=c-ab/÷b
x=c÷b-a
b)(x-a)b=c+a
bx-ab=c+a
bx=c+a-ab/÷b
x=c÷b+a÷b-a
zad2
(×+⅓)²-(×-2)(x+2)+⁸₉=(x+5)²-ײ+⅔×
x²+¹/₉-x²+2x-2x+4+⁹/₉=x²-x²+²/₃x
¹/₉+4+⁸/₉=²/₃x
²/₃x=5
x=3¹/₃