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wc=?
w1=?
dane:
h=25m
t1=1s
t2=1h=3600s
m=20l=20kg
wzór:
w1=f*h
f=m*g
w1=m*g*h
wc=w1*t2
rozw:
w1=20kg*10m/s2*25m [kg*m/s2=J]
w1=5KJ
wc=5KJ*3600
wc=18000KJ=18MJ
Odp:w czasie godziny pompa wykona prace 18 mega dżuli