wyznacz wartości funkcji f(x)=-x²-4x+1 dla x=3Ѵ2-2
f(3Ѵ2-2) = - (3Ѵ2-2)² - 4(3Ѵ2-2)+1 = - (18-12Ѵ2+4) -12Ѵ2+8+1=-22 +12Ѵ2- 12Ѵ2+9=-13
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f(3Ѵ2-2) = - (3Ѵ2-2)² - 4(3Ѵ2-2)+1 = - (18-12Ѵ2+4) -12Ѵ2+8+1=-22 +12Ѵ2- 12Ѵ2+9=-13