Wyznacz wartość a i b dla których pierwiastkiem wielomianu W(x)= + (4b+a) - (3b - a)x - 12 są liczby 2 i -3.
2³+[4b+a]×2²-[3b-a]×2-12=0
8+16b+4a-6b+2a-12=0
6a+10b=4
[-3]³+[4b+a]×[-3]²-[3b-a]×[-3]-12=0
-27+36b+9a-[-9b+3a]-12=0
-27+36b+9a+9b-3a-12=0
6a+45b=39
6a+10b=4/×-1
-6a-10b=-4
35b=35
b=1
6a+10×1=4
6a=4-10
6a=-6
a=-1
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2³+[4b+a]×2²-[3b-a]×2-12=0
8+16b+4a-6b+2a-12=0
6a+10b=4
[-3]³+[4b+a]×[-3]²-[3b-a]×[-3]-12=0
-27+36b+9a-[-9b+3a]-12=0
-27+36b+9a+9b-3a-12=0
6a+45b=39
6a+10b=4/×-1
6a+45b=39
-6a-10b=-4
35b=35
b=1
6a+10×1=4
6a=4-10
6a=-6
a=-1
a=-1
b=1