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f(x)=a(x+5)(x-2)
f(-3)=a(-3+5)(-3-2)=10
-10a=10
a=-1
f(x)=-(x+5)(x-2) iloczynowa
f(x)=-x²+2x-5x+10
f(x_=-x²-3x+10 postac ogolna
f(x)=a(x+5)(x-2)
f(-3)=a(-3+5)(-3-2)=10
-10a=10
a=-1
f(x)=-(x+5)(x-2 iloczynowa
f(x)=-x²+2x-5x+10
f(x_=-x²-3x+10 postac ogolna