wyznacz takie wspolczynniki a,b,c aby W(x)=P(x), gdy W(x)=a(x-2)(x-3) b(x-1)(x-3) +c(x-1)(x-2) i P(x)=5x^2 - 19x + 18 pełne rozwiązanie. na dzis
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wyznacz takie wspolczynniki a,b,c aby W(x)=P(x), gdy W(x)=a(x-2)(x-3) b(x-1)(x-3) +c(x-1)(x-2) i P(x)=5x^2 - 19x + 18
W(x)=a(x-2)(x-3) b(x-1)(x-3) +c(x-1)(x-2)
W(x) = a(x²-5x +6) ? b(x²-4x +3) +c(x²-3x +2)
przed b jaki ma być znak "+" czy "-"
Obliczam dla "+"
W(x) = ax² + bx² +cx² -5ax-4bx -3cx + 6a +3b +2c
W(x) = x²(a +b +c) - x(5a +4b +3c) + 6a +3b +2c
P(x) = 5x² - 19x + 18
W(x) = P(x) gdy odpowiednie współczynniki przy niewiadomych sa równe
a +b +c = 5
-(5a +4b +3c) = -19 /:(-1)
6a +3b + 2c = 18
Powstał układ 3 równań z 3 niewiadomymi
a = 5 -b -c
5a +4b +3c = 19
6a +3b + 2c = 18
a = 5 -b -c
5( 5 -b -c) +4b +3c = 19
6( 5 -b -c) +3b +2c = 18
a = 5 -b -c
25 -5b -5c+4b +3c = 19
30 -6b -6c +3b +2c = 18
a = 5 -b -c
-b -2c = 19 -25
-3b -4c = 18 -30
a = 5 -b -c
-b -2c = -6
-3b -4c = -12
a = 5 -b -c
-b = -6 +2c /:(-1)
-3b -4c = -12
a = 5 -b -c
b = 6 -2c
-3(6 -2c) -4c = -12
a = 5 -b -c
b = 6 -2c
-18 +6c -4c = -12
a = 5 -b -c
b = 6 -2c
2c = -12 +18
a = 5 -b -c
b = 6 -2c
2c = 6 /:2
a = 5 -b -c
b = 6 - 2*3 = 6 -6 = 0
c = 3
a = 5 -b -c
b = 0
c = 3
a = 5 - 0 -3 = 2
b = 0
c = 3
a = 2
b =0
c = 3