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a)w T przekształcamy tylko √2i7/9= √25/9=5/3
suma wynosi 2/3x⁴+5/3x⁴+x²+2x-3-1=7/3x⁴+x²-x-1=7/3*16+4-2-1=102/3+1=37i1/3+1=38i1/3
b) w S przekształcamy tylko 3/√3=3√3/3=√3
suma wynosi √3x³-√3x³+3x²-x²+2-1=2x²+1=2*4+1=9
6
Δ=b²-4ac
x₁=(-b-√Δ)/2a
x₂=(-b+√Δ)/2a
a)Δ=25-16=9
√Δ=3
x₁=(5-3)/2=1
x₂=(5+3)/2=4
x₃=0
b)Δ=16+84=100
√Δ=10
x₁=(-4-10)/2=-7
x₂=(-4+10)/2=3
x₃=0
c)Δ=1+24=25
√Δ=5
x₁=(-1-5)/4=-1i1/2
x₂=(-1+5)/4=1
x₃=0
d)Δ=9-16=-7<0
x=0