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Δ=121-4*30=1
n=1/2*(11-1)=5 v n=1/2*(11+1)=6
Odp. m.z. n∈{5, 6} , a₅=0 i a₆=0.
pierwiastek z delty = 1
x1 = [-(-11) - 1] : 2 = 5
x2 = (11 +1) :2 = 6
Odp : x1 = 5 x2 = 6