Wyznacz liczbę a tak, aby liczby: , a, a+3 w podanej kolejności tworzyły ciąg geometryczny.
a²=1/4 * (a+3)
a²=(a+3)/4
4a²=a+3
4a²-a-3=0
Δ=1-4*4*(-3)=1+48=49
√Δ=7
a₁=1-7/8 = -6/8 = -3/4
a₂=1+7/8=1
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a²=1/4 * (a+3)
a²=(a+3)/4
4a²=a+3
4a²-a-3=0
Δ=1-4*4*(-3)=1+48=49
√Δ=7
a₁=1-7/8 = -6/8 = -3/4
a₂=1+7/8=1