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x³-2x≠0
x(x²-2)≠0 ⇔ x≠0 ∧ x²-2≠0
x² ≠ 2 ⇔ x≠ -√2 ∧ x≠ √2 ; wiec D= R \ { - √2 ; 0 ; √2 }
Dziedzina tej funkcji jest: D=R \ { - √2 ; 0 ; √2 }.
dziedzina=R`{-√2,0,√2}