wyznacz cztery poczatkowe wyrazy ciagu arytmetycznego, w ktorym:
an=a1+(n-1)r
a1=1/2
r=2/3
a2=a1+r
a2=1/2+2/3=3/6+4/6=7/6 a2=7/6
a3=1/2+(3-1)*2/3=1/2+2*2/3=1/2+4/3=3/6+8/6=11/6=1 5/6 a3=1 5/6
a4=1/2+(4-1)*2/3=3/6+3*2/3=3/6+6/3=3/6+12/6=2 3/6=2 1/2 a4=2 1/2
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an=a1+(n-1)r
a1=1/2
r=2/3
a2=a1+r
a2=1/2+2/3=3/6+4/6=7/6 a2=7/6
a3=1/2+(3-1)*2/3=1/2+2*2/3=1/2+4/3=3/6+8/6=11/6=1 5/6 a3=1 5/6
a4=1/2+(4-1)*2/3=3/6+3*2/3=3/6+6/3=3/6+12/6=2 3/6=2 1/2 a4=2 1/2