wyznacz boki trójkata którefgo obwód jest równy 15 cm i jest on podobny do trójkąta o bokach 18, 24, 28 cm. Prosze o rozwiązanie
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Ob = 15cm
Ob` = 18 + 24 + 28 = 70cm
Ob` / Ob = k
k = 70/15
k = 14/3 ---- skala podobieństwa
a` = a * k
a = a` / k = 18 : 14/3 = 18 * 3/14 = 54/14 = 27/7 = 3 i 6/7cm
b = b` / k = 24 : 14/3 = 24 * 3/14 = 72/14 = 36/7 = 5 i 1/7cm
c = c` / k = 28 : 14/3 = 28 * 3/14 = 84/14 = 42/7 = 6cm