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(X³)²(x⁵)³ = x⁶*x¹⁵ = x²¹ (licznik)
[(x²)⁴]= x⁸ (mianownik)
x²¹/x⁸ = x¹³
b.4½-27⅓= 9/2-82/3 = 27/6-164/6 = -137/6 = -22⅚
c.(√7-3)(√7+3)= 7+3√7-3√7-9 = -2
d. 3√25+8√16 = 3*5+8*4 = 15+32 = 47
√144+5√49= = 12+5*7 = 12+35 = 47
b) zamieniam:9/2 - 82/3 ----> wspólny mianownik 27/6-164/6=-137/6 a to będzie -132 i 5/6
c)=(√7)²-3²=7-9=-2
d)3*5 + 8*4=47
√144=12 a √49=7 więc 12+5*7=47
[(x²)⁴]=x⁸
b) 4½-27⅓=√4-∛27=2-3=-1
c) (√7-3)(√7+3)=7-9=-2
d) 3√25+8√16=3*5+8*4=15+32=47
√144+5√49=12+5*7=12+35=47