Wykonaj podane działanie :
(√128 + √50) · √2
(√128 + √50) · √2 = √128 * √2 + √50 * √2 = √(128 * 2) + √(50 * 2) = √256 + √100 = 16 + 10 = 26
(√128 + √50) x √2 = (√2 x √64 + √2 x √25) x √2 = (√2 x 8 + √2 x 5) x √2 = √2 x √2 x 8 + √2 x √2 x 5 = 2 x 8 + 2 x 5 = 16 + 10 = 26
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Pozdrawiam :)
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(√128 + √50) · √2 = √128 * √2 + √50 * √2 = √(128 * 2) + √(50 * 2) = √256 + √100 = 16 + 10 = 26
(√128 + √50) x √2 = (√2 x √64 + √2 x √25) x √2 = (√2 x 8 + √2 x 5) x √2 = √2 x √2 x 8 + √2 x √2 x 5 = 2 x 8 + 2 x 5 = 16 + 10 = 26
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)