Question

wykonaj mnozenie i zredukujwyrazy podobne

(x-7)*(2x^2-5x+8)

(r+3)*(4r^2-4r+5)

(x^2-x+1)*(x+1)

(6h+8)*(4x+3)*(4x-3)

(5a-4c)*(5a+4c)

Answer 1

 (x-7)*(2x^2-5x+8) = 2x³ - 5x² + 8x - 14x² + 35x - 56 = 2x³ - 19x² + 43x - 56

 (r+3)*(4r^2-4r+5) = 4r³ - 4r² + 5r + 12r² - 12r + 15 = 4r³ + 8r² - 7r + 15

 (x^2-x+1)*(x+1) = x³ + x² - x² - x +x + 1 = x³ + 1

 (6h+8)*(4x+3)*(4x-3) = (6h + 8) * (16x² - 9) = 96hx² - 54h + 128x² - 72

 (5a-4c)*(5a+4c) = 25a² - 16c²

Answer 2

a)(x-7)*(2x^2-5x+8)=2x^3-5x^2+8x-14x^2+35x-56=2x^3-19x^2+43x-56

b)(r+3)*(4r^2-4r+5)=4r^3-4r^2+5r+12x^2-12r+15=4r^3+8r^2-7r+15

c)(x^2-x+1)*(x+1)=x^3+x^2-x^2-x+x+1=x^3+1

d)(6h+8)*(4x+3)*(4x-3)=24hx+18h+24hx+18h+32x+24+32x-24=48hx+36h+64x

e)(5a-4c)*(5a+4c)=25a^2+20ac-20ac-16c^2=25a^2-16c^2

 

mam nadzieje z ewszystko jest dobrze licze na naj