Question

Wykonaj mnożenie

(x+y+3)*(2x-y)

(3x-1)*(3x+1)*(2-x)

(3xy-y+3x)*(3z-xy+y)

[2x-(b+a)]*[(a+b)+2x]

2

(x+4)*(x-2)*(x+2)

2 2

(2x-y)*(2x+y)*(4x +y )

2

Jak jest np. x to jest potęga

z góry dzięki

Answer 1

(x+y+3)*(2x-y)

2 2

2x-y+3

(3x-1)*(3x+1)*(2-x)

-9x-2

Answer 2

Wykonaj mnożenie

(x+y+3)*(2x-y) = 2x²-xy+2xy-y²+6x-3y = 2x²-y²+xy+6x-3y

(3x-1)*(3x+1)*(2-x) = (9x²-1)*(2-x) = 18x²-9x³-2+x = -9x³+18x²+x-2

(3xy-y+3x)*(3z-xy+y) = 9xyz-3x²y²+3xy²-3yz+xy²-y²+9xz-3x²y+3xy = -3x²y²-3x²y+4xy²-y²+9xyz+3xy+9xz-3yz

[2x-(b+a)]*[(a+b)+2x]=(2x-b-a)(a+b+2x)=2xa+2xb+4x²-ab-b²-2xb-a²-ab-2xa=4x²-a²-b²-2ab

 

 

(x²+4)*(x-2)*(x+2)=(x²+4)(x²-4)==x⁴-16

                        

(2x-y)*(2x+y)*(4x² +y² )=(4x²-y²)(4x²+y²)=16x⁴-y⁴