wykonaj działania
x+y
x-y
x·y
x₂
gdzie x to √3+ 2
a y to 4√3-1
x+y=√3+2+4√3-1=5√3+1
x-y=√3+2-4√3+1=-3√3+3
x×y=(√3+2)(4√3-1)=4×3-√3+6√3-2=12+5√3-2=10+5√3
√3+2 +4√3-1=5√3+1
√3+2 -(4√3 -1)= √3+2-4√3+1=-3√3+3
(√3+2)*(4√3-1)= 12 -√3 +8√3 -2= 7√3+10
(√3+2)2= 3+4√3+4=4√3+7
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x+y=√3+2+4√3-1=5√3+1
x-y=√3+2-4√3+1=-3√3+3
x×y=(√3+2)(4√3-1)=4×3-√3+6√3-2=12+5√3-2=10+5√3
√3+2 +4√3-1=5√3+1
√3+2 -(4√3 -1)= √3+2-4√3+1=-3√3+3
(√3+2)*(4√3-1)= 12 -√3 +8√3 -2= 7√3+10
(√3+2)2= 3+4√3+4=4√3+7