Wykaż, że log12=a i log2=b, oblicz log90
log90=log(10*9)=log10+log9=log10+log3²=log10+2log3=1+2log3
a=log12=log(4*3)=log4+log3=log2²+log3=2log2+log3
a=2log2+log3
b=log2
a=2b+log3
log3=a-2b
log90=1+2log3=1+2(a-2b)=1 +2a- 4b
log90=1 +2a -4b
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log90=log(10*9)=log10+log9=log10+log3²=log10+2log3=1+2log3
a=log12=log(4*3)=log4+log3=log2²+log3=2log2+log3
a=2log2+log3
b=log2
a=2b+log3
log3=a-2b
log90=1+2log3=1+2(a-2b)=1 +2a- 4b
log90=1 +2a -4b