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ab + bc + ac ≥ a√(bc) + b√(ac) + c√(ab) wszytko razy 2
ab+ab+bc+bc+ac+ac ≥2a√bc+2b√ac+2c√ab
a(b+c)+b(a+c)+c(a+b)≥2a√bc+2b√ac+2c√ab
a(b+c)≥2a√bc b+c≥2√bc
b(a+c)≥2b√ac a+c≥2√ac
c(a+b)≥2c√ab a+b≥2√ab
L≥P