Wykaż, że ciąg jest geometryczny
an = p(3)/[ 2^(n +3)] = p(3)/ [ 8*2^n ]
zatem
an+1 = p(3)/ [ 8* 2^(n +1)] = p(3) / [ 8*2* 2^n] = p(3)/[ 16 * 2^n]
Mamy więc
an+1 : an = 1/2 = q
Jest to ciąg geomatryczny o ilorazie q = 1/2
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an = p(3)/[ 2^(n +3)] = p(3)/ [ 8*2^n ]
zatem
an+1 = p(3)/ [ 8* 2^(n +1)] = p(3) / [ 8*2* 2^n] = p(3)/[ 16 * 2^n]
Mamy więc
an+1 : an = 1/2 = q
Jest to ciąg geomatryczny o ilorazie q = 1/2
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