Question

Wyłączanie wspólnego czynnika przed nawias.

np.5ײ-15x=5×(×-3)

×y-ײy=
6a-24b+30c=
12ab²+16b²=
׳-2׳+×=
2×y+3×-x²y=

Answer 1

×y-ײy=xy(x-1)
6a-24b+30c=6(a-4b+5c)
12ab²+16b²=4b²(3a+4)
׳-2׳+×=x(x²-2x²+1)
2×y+3×-x²y=x(2y+3-xy)

Answer 2

×y-ײy=xy(1-x)
6a-24b+30c=6(a-4b+5c)
12ab²+16b²=4b^2(3a+4)
׳-2׳+×=x^3(1-2)
2×y+3×-x²y= x(2y+2-xy)

Answer 3

Xy-x2y=xy(1-x)
6a-24b+30c=6(a-4b+5c)
12ab2+16b2=4(3ab2+4b2)
x3-2x3+x=x(x2-2x2+1)
2xy+3x-x2y=x(2y+3-xy)