September 2018 2 13 Report

W(x)=x³-3x²-4x+d

dla x=-2 wielomian W(x)=0 czyli W(-2)=0

stąd

(-2)³-3(-2)²-4(-2)+d=0

d=-(-2)³+3(-2)²+4(-2)

d=-8+12-8

d=12

x³-3x²-4x+12=0

x³-4x-3x²+12=0

x(x²-4)-3(x²-4)=0

(x-3)(x²-4)=0

(x-3)(x+2)(x-2)=0

W(x)=0 gdy:(x-3)=0 lub (x+2)=0 lub (x-2)=0

szukane pierwiastki to 3, -2, 2

Ktos moze mi powiedziec czemu tutaj wyszlo 12 ? mi wychodzi -4.Prosz o pomoc

d=-8+12-8

d=12


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