Witam> Prosze o pomoc!!!1
(x-2)(x+2)+4>(x-2)2(do kwadratu). Zalezy mi na czasie.. Z góry dzx.Potrzebne na teraz
(x-2)*(x+2)+4>(x-2)^2
x^2-4+4>x^2-4x+4
x^2-x^2+4x>4+4-4
4x>4 I:4
x>1
x^2 --->x do kwadratu
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(x-2)*(x+2)+4>(x-2)^2
x^2-4+4>x^2-4x+4
x^2-x^2+4x>4+4-4
4x>4 I:4
x>1
x^2 --->x do kwadratu