Question

Witam :)

Proszę o pomoc w fizyce.

"prawo powszechnego ciążenia. Spadanie ciał"

Zastosować trzeba wzór F = G * m1*m2

______

r²

Answer 1

zad.1.

m₁ = 20g = 0,02 kg = 2*10⁻² kg

m₂ = 10 g = 0,01 kg = 10⁻² kg

r = 4 cm = 0,04 m = 4*10⁻² m

G = 6,67 *10⁻¹¹ N * m²/kg²

F = ?

F = G * m₁*m₂/r²

F = 6,67 *10⁻¹¹ N * m²/kg² * 2 *10⁻²kg * 10⁻² kg /(4 *10⁻² m )²

F = 13,34 *10⁻¹⁵ N * m² / 16 *10⁻⁴ m²

F ≈ 0,834 *10⁻¹¹ N ≈ 8,34 *10⁻¹⁰ N

 

zad.2.

M = 10 kg

m = 50 g = 0,05 kg = 5 *10⁻² kg

r = 1 cm = 0,01 m = 10⁻² m

G = 6,67 *10⁻¹¹ N * m²/kg²

F = ?

F = G * m₁*m₂/r²

F = 6,67 *10⁻¹¹ N * m²/kg² * 10 kg *5  *10⁻²kg  /(10⁻² m )²

F = 333,5 *10⁻¹³ N*m²/10⁻⁴ m²

F = 333,5 *10⁻⁹ N

 

zad.3.

M = 6 *10²⁴ kg

R = 6370 km = 6370000 m = 6,37 *10⁶ m

G = 6,67 *10⁻¹¹ N * m²/kg²

g = ?

 

m*g = G * M *m/R²

g = G * M /R²

g = 6,67 *10⁻¹¹ N * m²/kg² * 6 *10²⁴ kg /(6,37 *10⁶ m)²

g = 40,02 *10¹³ N * m²/kg  /40,48 *10¹² m²

g ≈ 0,989 *10 N /kg

g ≈9,89 kg * m/s² /kg

g ≈ 9,89 m/s²

 

zad.4.

m₁ = 10 g = 0,01 kg = 10⁻² kg

m₂ = 5 kg

r = 3 cm = 0,03 m = 3 *10⁻² m

G = 6,67 *10⁻¹¹ N * m²/kg²

F = ?

F = G * m₁*m₂/r²

F = 6,67 *10⁻¹¹ N * m²/kg² * 5 kg  *10⁻²kg  /(3 *10⁻² m )²

F = 33,35 *10⁻¹³ N * m² /9 *10⁻⁴ m²

F ≈ 3,7 *10⁻⁹ N