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ΔE=E fotomu(kwantu)
E=?
A=13,6eV=21,8 *10 (do -19)J
1eV=1,6*10 (do -19)J
n=5
k=1
E=21,8 *10 (do -19)J(1/5-1/1)
E=21,8 *10 (do -19)J(1/5-5/5)
E=21,8 *10 (do -19)J*-4/5
E=-87,2*10(do -19)J / 5
E=-17,44*10(do -19)J
mam nadzieje ze pomoglam ;)