Wiedząc,że ctg alfa=pierwiastek z 3,oblicz pozostałe proporcje trygoometryczne.
tgα=1/ctgα
tgα=1/√3=√3/3
tgα=sinα/cosα
sinα/cosα=√3/3
sinα=√3cosα/3
sin²α+cos²α=1
⅓cos²α+cos²α=1
4/3cos²α=1
cos²α=¾
cosα=√3/2
sinα=√3/3·√3/2=3/6=½
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tgα=1/ctgα
tgα=1/√3=√3/3
tgα=sinα/cosα
sinα/cosα=√3/3
sinα=√3cosα/3
sin²α+cos²α=1
⅓cos²α+cos²α=1
4/3cos²α=1
cos²α=¾
cosα=√3/2
sinα=√3/3·√3/2=3/6=½