Janek191
W(x) = 2 x³ + m x² - 13 x + n 2 oraz 3 pierwiastki wielomianu zatem 2* 2³ + m*2² - 13*2 + n = 0 2*3³ + m*3² - 13*3 + n = 0 -------------------------------- 16 + 4 m - 26 + n = 0 54 + 9 m - 39 + n = 0 -------------------------------- 4 m + n - 10 = 0 9 m + n + 15 = 0 ----------------------- odejmujemy stronami 9 m - 4 m +25 = 0 5 m = - 25 m = -5 n = 10 - 4 m = 10 - 4*(-5) = 10 +20 = 30 Odp. m = -5 oraz n = 30 ==============================
W(x) = 2x³ + mx² - 13x + n
W(2) = 0
W(3) = 0
m = ?
n = ?
W(2) = 2*2³ + m*2² - 13*2 + n
W(2) = 2*8 + m*4 - 26 + n
W(2) = 16 + 4m - 26 + n
W(2) = 4m + n - 10
W(3) = 2*3³ + m*3² - 13*3 + n
W(3) = 2*27 + m*9 - 39 + n
W(3) = 54 + 9m - 39 + n
W(3) = 9m + n + 15
{ 4m + n - 10 = 0
{ 9m + n + 15 = 0
{ 4m + n = 10
{ 9m + n = - 15
5m = - 25 /: 5
{ m = - 5
{4*(- 5) + n = 10
{ m = - 5
{- 20 + n = 10
{ m = - 5
{ n = 30
Odp: m = - 5 , n = 30.
2×2³+2²m-13×2+n=0; 16+4m-26+n=0;
2×3³+3²m-13×3+n=0; 54+9m-39+n=0;
rozwiązuję ukł. równań ;
4m+n-10=0;/×(-1)
9m+n+15=0;
-4m-n+10=0;
9m+n+15=0;
5m+25=0;
5m=-25/:5; m=-5 ; 9m+n+15=0 ; 9×(-5)+n+15=0 ;n=30
2 oraz 3 pierwiastki wielomianu
zatem
2* 2³ + m*2² - 13*2 + n = 0
2*3³ + m*3² - 13*3 + n = 0
--------------------------------
16 + 4 m - 26 + n = 0
54 + 9 m - 39 + n = 0
--------------------------------
4 m + n - 10 = 0
9 m + n + 15 = 0
----------------------- odejmujemy stronami
9 m - 4 m +25 = 0
5 m = - 25
m = -5
n = 10 - 4 m = 10 - 4*(-5) = 10 +20 = 30
Odp. m = -5 oraz n = 30
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